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I'm looking to find X and Y.
Angles on the 20m side are 90deg. The angle between 3,66m and the base is 45deg.
The distance between Y and the end of the shape is approx, 1,520m so let's use this value to determine the real length of this top side: 12,23m.
How do I find X and Y's height?
(https://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pnghttps://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pngI'mlookingforthevalues(height)ofXandY.Anglesonthe20msideare90degrees.Anglebetween3,66mandthebaseis45degrees.ThedistancebettweenYandtheendoftheshapeisabout1,520m,solet'sassumeitisthat,forthesakeofsimplicity.)
I've settled a few problems of triggernometry in the court of judge Colt and his jury of six, sure.
My math classes we just a blur of trying to read books under my textbook, and achingly long boredom boners.
So the angle on the top left is not 90 degrees as shown? Or to what are you referring as the base?
Find out the scale of the drawing and then just measure it.
Tu es sûr que la mesure de ton angle à la base est de 45? Parce qu'avec ces mesures, ça donne plutôt un angle de 79 degrés.
Pour rappel, le tan de l'angle à la base, c'est le rapport du côté opposé (20) sur le côté adjacent (3,66).
Edit: Et si l'angle est bien 79,46 alors y vaut environ 28 cm, et x, environ 2.51 m.
Quote from: Oexmelin on June 08, 2017, 06:23:17 PM
Tu es sûr que la mesure de ton angle à la base est de 45? Parce qu'avec ces mesures, ça donne plutôt un angle de 79 degrés.
Pour rappel, le tan de l'angle à la base, c'est le rapport du côté opposé (20) sur le côté adjacent (3,66).
Edit: Et si l'angle est bien 79,46 alors y vaut environ 28 cm, et x, environ 2.51 m.
le dessin n'est pas à l'échelle, je l'ai fait moi même. ça n'est possiblement pas 45 degrés, mais bon, je le mesurerai. ça aurait été plus simple si l'ingénieur m'avait donné les mesures... <soupir>
Je croyais que la tangente ne valait que pour un triangle rectangle parfait et non pour un polygone irrégulier?
Je vais voir demain avec le dessin imprimé, ou idéalement, si l'ingénieur peut me donner les vraies mesures cette fois-ci.
@Maximus: top left is 90 degrees. Bottom left, let's assume it's 79 degrees as Oex said, I'll measure it on the printed plans since my softwares can't give me angles or measurement for such drawings.
Quote from: Maladict on June 08, 2017, 05:20:21 PM
Find out the scale of the drawing and then just measure it.
I do not have this elevation on the drawing. I made it myself with a free cad software. My skills... lie elsewhere than in drawing :P
All it says is "variable height". If it was that simple, I would have done it by finding the scale (it isn't even written <sigh> ) :)
Usually, engineers give me a nice view and they give me the height at each side. This one... well, neither the client nor his engineer seems to know exactly what they want.
Quote from: CountDeMoney on June 08, 2017, 04:30:20 PM
My math classes we just a blur of trying to read books under my textbook, and achingly long boredom boners.
I dreamt of DeAnna Zimmer who sat in the seat in front of me. Hot as hell and had these long legs that.....
Excuse me. Sorry Viper.
I don't think your graph works, unless I'm misunderstanding something. If the bottom left angle is 45 degrees, the black line at the bottom should be crossing the top line 3.66 m in, yet in your picture it doesn't cross it even after 20 meters.
Quote from: DGuller on June 08, 2017, 08:05:46 PM
I don't think your graph works, unless I'm misunderstanding something. If the bottom left angle is 45 degrees, the black line at the bottom should be crossing the top line 3.66 m in, yet in your picture it doesn't cross it even after 20 meters.
I think he was saying the top left angle is 45 degrees, but not sure.
Quote from: Maximus on June 08, 2017, 08:44:43 PM
I think he was saying the top left angle is 45 degrees, but not sure.
He is saying he was told the bottom left angle is 45, but, as I have told him, it doesn't work with the rest of the measurements, assuming the top left angle is indeed 90.
Assuming the 45 degree angle thing is a red herring, you can get the values without really knowing Trig since you don't care about the angles.
3.66/20 = .183
That's the ratio of height to length.
x/(20-6.25)=.183
x=13.75*.183=2.51625
y/1.52=.183
y=1.52*.183=.27816
x=2.51625
y=.27816
Which I think is what Oex said above.
There's no way the info you've given us adds up.
Given the two legs of the right triangle, the tangent tells me the non-square angle of the 3.66m line is 79.6296 degrees, not 45.
Furthest I can get with the dimensions given is that the distance of the hypotenuse from the 3.66m side to where it meets line X is 6.3538m. Since the two lines run parallel, there doesn't seem to be any way to figure out how far up or down the legs the 6.25m measure line is.
Quote from: DontSayBanana on June 08, 2017, 09:32:00 PM
There's no way the info you've given us adds up.
Given the two legs of the right triangle, the tangent tells me the non-square angle of the 3.66m line is 79.6296 degrees, not 45.
Furthest I can get with the dimensions given is that the distance of the hypotenuse from the 3.66m side to where it meets line X is 6.3538m. Since the two lines run parallel, there doesn't seem to be any way to figure out how far up or down the legs the 6.25m measure line is.
The green lines are the measurements, they aren't part of the shape.
Quote from: frunk on June 08, 2017, 09:35:01 PM
The green lines are the measurements, they aren't part of the shape.
Actually, now that I think about it, that can get me the length of side x- the difference between 3.66 and the length of the shorter side of the smaller triangle with that leg would be the length of side x, which is 2.5162m. I really don't see a way to extract side y's dimension from this diagram, though.
There is simply not enough information here. You have to know the bottom left angle, otherwise there is too much freedom here. There is no information here that constrains what y can be, it can be anything. Once you know the bottom left angle, then you can figure out the length of all the pieces.
If you gave me multiple triangles, I could tell you if there's a statistically significant difference in the lengths of their sides. :)
Quote from: DGuller on June 08, 2017, 09:46:00 PM
There is simply not enough information here. You have to know the bottom left angle, otherwise there is too much freedom here. There is no information here that constrains what y can be, it can be anything. Once you know the bottom left angle, then you can figure out the length of all the pieces.
Never mind, the 20m is the lenth to the hypotenuse, not to y meeting point, so you can calculate the angle. But there is still one piece of measurement missing to calculate y, you need one more measurement to fix its location.
I am not good at math, or trigonometry. The way I did it at school was to draw a to-scale model of the triangle and measure the length.
Quote from: DGuller on June 08, 2017, 09:55:13 PM
Never mind, the 20m is the lenth to the hypotenuse, not to y meeting point, so you can calculate the angle. But there is still one piece of measurement missing to calculate y, you need one more measurement to fix its location.
Exactly. That's how I got side x, but without a measurement to the right of it, y isn't differentiable.
Quote from: DGuller on June 08, 2017, 09:55:13 PM
Never mind, the 20m is the lenth to the hypotenuse, not to y meeting point, so you can calculate the angle. But there is still one piece of measurement missing to calculate y, you need one more measurement to fix its location.
QuoteThe distance between Y and the end of the shape is approx, 1,520m
Assuming that is horizontal distance, y = 1.52 / tan(79).
Quote from: Oexmelin on June 08, 2017, 08:47:26 PM
He is saying he was told the bottom left angle is 45, but, as I have told him, it doesn't work with the rest of the measurements, assuming the top left angle is indeed 90.
top is 90 degrees, that's about the only thing I'm sure of. And the total lenght of the alley, wich is different from the total lenght of the wall.
Thinking of it, the bottom left won't be 45 degrees, that inclination is too steep.
As I said usually, for these kind of project, I'm given an elevation view and I know at least two lengths (the 3,66m) and the y and the total length of the wall. Now I have to guess some of the measurements.
Quote from: DontSayBanana on June 08, 2017, 09:32:00 PM
There's no way the info you've given us adds up.
Given the two legs of the right triangle, the tangent tells me the non-square angle of the 3.66m line is 79.6296 degrees, not 45.
Furthest I can get with the dimensions given is that the distance of the hypotenuse from the 3.66m side to where it meets line X is 6.3538m. Since the two lines run parallel, there doesn't seem to be any way to figure out how far up or down the legs the 6.25m measure line is.
Here is what I have.
Contrary to the second drawing, there won't be a wall to the end, that's just not very practical to do below 300mm (12"), I'll stop short of the end, so the wall will never be 1 or 2 cm. But approximation is what I need for now. Once the client and the engineers have settled on the final design, they'll give me their measurement. But I need to submit a price first.
The walls for EE and FF are the ones I'm trying to determine the height at the end. I know EE starts at 12' (3,66m). I know there is a slope in the floor of 1:8, I just noticed it. I know at the very end of 20m I am at 0, but my wall will not extend up to there. And since there's two different type of walls, it's a little trickier than usual to measure my steel rebars lenght.
I think I'm ok now that I see the slope. Benefits of rested eyes. :)
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Quote from: Monoriu on June 08, 2017, 09:55:35 PM
I am not good at math, or trigonometry. The way I did it at school was to draw a to-scale model of the triangle and measure the length.
that's what my colleague just told me :P
But I want the formula for Excel, so my bidding software is future proof.
I can see this thread being printed out during the discovery process of some malpractice civil suit in the future. :(
W.A.S.P. - Animal (Fuck Like A Beast)
Quote from: DGuller on June 09, 2017, 09:05:13 AM
I can see this thread being printed out during the discovery process of some malpractice civil suit in the future. :(
-How do you plead?
-Not guilty. Languish did it.
Quote from: viper37 on June 09, 2017, 08:42:17 AM
that's what my colleague just told me :P
But I want the formula for Excel, so my bidding software is future proof.
It's not just one formula- it depends which pieces of the triangle you have. For right triangles, you can reconstruct all the angles and sides from either one side and an angle or two sides. For non-right triangles, you need at least one side and all three angles (technically, two, but if you have two angles, you've got all three since they add up to 180), so you can determine where to split it into two right triangles.
High school math is cool. One of my favorite questions that I remember from a test was about a cone inscribed in a sphere. The height of the cone is increased. At which height does the height and radius of the cone increase at the same rate?
Quote from: DontSayBanana on June 09, 2017, 04:44:24 PM
Quote from: viper37 on June 09, 2017, 08:42:17 AM
that's what my colleague just told me :P
But I want the formula for Excel, so my bidding software is future proof.
It's not just one formula- it depends which pieces of the triangle you have. For right triangles, you can reconstruct all the angles and sides from either one side and an angle or two sides.
Yes, I was trying to fit a right angle triangle somewhere, to first deduce the missing side, then try my luck with the other part.
QuoteFor non-right triangles, you need at least one side and all three angles (technically, two, but if you have two angles, you've got all three since they add up to 180), so you can determine where to split it into two right triangles.
yeah, that's what I was missing. Anyway, I got my measurements thanks to funk and my colleague. Close enough for now. Before I hit the site I'll ask for a more detailed view.
Quote from: The Brain on June 09, 2017, 04:51:33 PM
High school math is cool. One of my favorite questions that I remember from a test was about a cone inscribed in a sphere. The height of the cone is increased. At which height does the height and radius of the cone increase at the same rate?
that's not something we do in high school. I remember such questions, but they were in the calculus class in college (1st year after high school, so "grade 12" if you don't count kindergarden).
All we deed in high school, in advanced math, was to draw figures. Find the equation, draw the curve, get noted on how well you drew the curve or the shape.
Quote from: viper37 on June 09, 2017, 05:08:51 PM
Quote from: The Brain on June 09, 2017, 04:51:33 PM
High school math is cool. One of my favorite questions that I remember from a test was about a cone inscribed in a sphere. The height of the cone is increased. At which height does the height and radius of the cone increase at the same rate?
that's not something we do in high school. I remember such questions, but they were in the calculus class in college (1st year after high school, so "grade 12" if you don't count kindergarden).
All we deed in high school, in advanced math, was to draw figures. Find the equation, draw the curve, get noted on how well you drew the curve or the shape.
Ouch. With finger paint?
Quote from: The Brain on June 09, 2017, 05:11:42 PM
Quote from: viper37 on June 09, 2017, 05:08:51 PM
Quote from: The Brain on June 09, 2017, 04:51:33 PM
High school math is cool. One of my favorite questions that I remember from a test was about a cone inscribed in a sphere. The height of the cone is increased. At which height does the height and radius of the cone increase at the same rate?
that's not something we do in high school. I remember such questions, but they were in the calculus class in college (1st year after high school, so "grade 12" if you don't count kindergarden).
All we deed in high school, in advanced math, was to draw figures. Find the equation, draw the curve, get noted on how well you drew the curve or the shape.
Ouch. With finger paint?
close ;)
Quote from: viper37 on June 08, 2017, 04:25:06 PM
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I'm looking to find X and Y.
Angles on the 20m side are 90deg. The angle between 3,66m and the base is 45deg.
The distance between Y and the end of the shape is approx, 1,520m so let's use this value to determine the real length of this top side: 12,23m.
How do I find X and Y's height?
(https://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pnghttps://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pngI'mlookingforthevalues(height)ofXandY.Anglesonthe20msideare90degrees.Anglebetween3,66mandthebaseis45degrees.ThedistancebettweenYandtheendoftheshapeisabout1,520m,solet'sassumeitisthat,forthesakeofsimplicity.)
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Quote from: 11B4V on June 09, 2017, 08:16:55 PM
Quote from: viper37 on June 08, 2017, 04:25:06 PM
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I'm looking to find X and Y.
Angles on the 20m side are 90deg. The angle between 3,66m and the base is 45deg.
The distance between Y and the end of the shape is approx, 1,520m so let's use this value to determine the real length of this top side: 12,23m.
How do I find X and Y's height?
(https://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pnghttps://postimg.org/image/f0cu42hzl/%5Dhttps://s24.postimg.org/f0cu42hzl/Test.pngI'mlookingforthevalues(height)ofXandY.Anglesonthe20msideare90degrees.Anglebetween3,66mandthebaseis45degrees.ThedistancebettweenYandtheendoftheshapeisabout1,520m,solet'sassumeitisthat,forthesakeofsimplicity.)
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L.